2n^2-2n-1136=0

Solution for 2n^2-2n-1136=0 equation:

2n^2-2n-1136=0

a = 2; b = -2; c = -1136;
Δ = b2-4ac
Δ = -22-4·2·(-1136)
Δ = 9092
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9092}=\sqrt{4*2273}=\sqrt{4}*\sqrt{2273}=2\sqrt{2273}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{2273}}{2*2}=\frac{2-2\sqrt{2273}}{4}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{2273}}{2*2}=\frac{2+2\sqrt{2273}}{4}
$